Issue
How do I get and print the meta content?
Like the profile picture(avator circle)title, username(subTitle), description(des), followers(val), following(val), instagram(profile-link_media), website(profile-link_href) and list of video urls if available.
Code:
from bs4 import BeautifulSoup
import requests
url = "https://likee.video/@HouseofB"
req = requests.get(url)
soup = BeautifulSoup(req.content, "html.parser")
print(soup)
I am trying to do something like:
from bs4 import BeautifulSoup
import requests
url = "https://likee.video/@HouseofB"
req = requests.get(url)
soup = BeautifulSoup(req.content, "html.parser")
des = soup.find('meta', attrs={'name':'description'})
print(des)
But I can't quite get it to work getting the information as sorted above mentioned.
I want to print it like this:
Profile picture: url
User: HouseofBrooklyn
Userid: @HouseofB
Followers: 8.6M
Likes: 64.0M
Instagram: url
Website: url
Videos:
list of urls
In advance, thank you for your kind help at teaching me!
Solution
You can get the desired data from API.As data is loaded dynamically by JS via API which is POST
method.
Example:
import requests
payload = {"likeeId":"HouseofB"}
headers= {
'content-type': 'application/json'}
api_url='https://api.like-video.com/likee-activity-flow-micro/official_website/WebView/getProfileDetail'
req=requests.post(api_url,headers=headers,json=payload).json()
print(req)
out=[]
out.append({
'User Name':req['data']['userinfo']['user_name'],
'Followers': req['data']['userinfo']['fansCount'],
'Link':req['data']['userinfo']['link'],
'Likes':req['data']['userinfo']['allLikeCount'],
'img_link':req['data']['userinfo']['data1']
})
print(out)
Answered By - F.Hoque
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