[FIXED] How do I sort a python dictionary values and rearrange keys?

Issue

How can I sort the following dictionary by its values and rearrange keys?.

{1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 1, 1, 1], 4: [1, 0, 1, 1]}

Expected result :

{1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 0, 1, 1], 4: [1, 1, 1, 1]}

Solution

The easiest way is to create a new dictionary by combining the keys and the sorted values from the original dict. Assign that dict to the original variable, and you're done.

In [1]: orig = {1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 1, 1, 1], 4: [1, 0, 1, 1]}
Out[1]: {1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 1, 1, 1], 4: [1, 0, 1, 1]}

In [2]: k = list(orig.keys())
Out[2]: [1, 2, 3, 4]

In [3]: v = sorted(orig.values())
Out[3]: [[0, 0, 1, 1], [0, 1, 1, 1], [1, 0, 1, 1], [1, 1, 1, 1]]

In [4]: orig = dict(zip(k, v))
Out[4]: {1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 0, 1, 1], 4: [1, 1, 1, 1]}

It can even be done in a single line:

In [1]: orig = {1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 1, 1, 1], 4: [1, 0, 1, 1]};

In [2]: orig = dict(zip(orig.keys(), sorted(orig.values())))
Out[2]: {1: [0, 0, 1, 1], 2: [0, 1, 1, 1], 3: [1, 0, 1, 1], 4: [1, 1, 1, 1]}

Answered By - Roland Smith