Issue
I have a problem, when I am creating a Label in function (def), and after I am trying to destroy this Label, using other fucntion (def), it says, that lab2 is not defined
from tkinter import*
root=Tk()
root.geometry("500x300")
def com1():
global lab, but
lab.destroy()
but.destroy()
lab=Label(text="Label 2")
lab.place(x=237, y=27)
but=Button(text="Go to first screen", command=com2)
but.place(x=200, y=57)
lab2=Label(text="Label 3")
lab2.place(x=220, y=107)
def com2():
global lab, but
lab.destroy()
but.destroy()
lab2.destroy()
lab=Label(text="Label")
lab.place(x=237, y=27)
but=Button(text="Go to second screen", command=com1)
but.place(x=200, y=57)
lab=Label(text="Label")
lab.place(x=237, y=27)
but=Button(text="Go to second screen", command=com1)
but.place(x=200, y=57)
root.mainloop()
How can i create a Label if fucntion(def) and make it so, that other functions(defs) could see it and, for example, destroy it
Solution
just global lab2:
from tkinter import*
root=Tk()
root.geometry("500x300")
def com1():
global lab, but,lab2
lab.destroy()
but.destroy()
lab=Label(text="Label 2")
lab.place(x=237, y=27)
but=Button(text="Go to first screen", command=com2)
but.place(x=200, y=57)
lab2=Label(text="Label 3")
lab2.place(x=220, y=107)
def com2():
global lab, but,lab2
lab.destroy()
but.destroy()
lab2.destroy()
lab=Label(text="Label")
lab.place(x=237, y=27)
but=Button(text="Go to second screen", command=com1)
but.place(x=200, y=57)
lab=Label(text="Label")
lab.place(x=237, y=27)
but=Button(text="Go to second screen", command=com1)
but.place(x=200, y=57)
root.mainloop()
have fun :)
Answered By - nariman zaeim
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