[FIXED] I need to merge these two lists together in python

Issue

listA = [['a','1'],['e','5'],['i','3'],['o','7'],['u','3']]
listB = [['a','6'],['b','3'],['c','4'],['d','1'],['e','2']]

Now, these lists represent item count. And i want to merge these two lists so that i can see the count of each item in the other list as well.

If an item is present in one list and is not present in the other list, then i want to state that as '0' rather than null. As shown below:

output = [['a','1','6'],['e','5','2'],['i','3','0'],['o','7','0'],
      ['u','3','0'],['b','0','3'],['c','0','4'],['d','0','1']]

Edit: Just to clarify the question for future reference. It has already been answered.

Solution

listA = [['a','1'],['e','5'],['i','3'],['o','7'],['u','3']]
listB = [['a','6'],['b','3'],['c','4'],['d','1'],['e','2']]

dictA = dict(listA)
dictB = dict(listB)

result = []

for key, value in listA:
  result.append([key, value, dictB.get(key, '0')])

for key, value in listB:
  if key not in dictA:
    result.append([key, '0', value])

print(result)
# [['a', '1', '6'], ['e', '5', '2'], ['i', '3', '0'], ['o', '7', '0'], ['u', '3', '0'], ['b', '0', '3'], ['c', '0', '4'], ['d', '0', '1']]

Answered By - bug