[FIXED] Python boolean comparison: False == not(True) SyntaxError

Issue

The following expression is evaluated to True

In [1]: not(True) == False
Out[2]: True

However, changing the order of evaluation returns a strange result!

In [3]: False == not(True)
  File "<stdin>", line 1
    (False == not(True))
                ^
SyntaxError: invalid syntax

What am I doing wrong?

Solution

You have to use the below code:

>>> False == (not True)
True
>>> 

Because the code runs from left to right, so it would first run False == not which is a SyntaxError.

>>> False == not
SyntaxError: invalid syntax
>>> 

Answered By - U12-Forward