[FIXED] Beautiful Soup. How to get a link containing a specific word?

Issue

HTML contains strings in divs:

• 'div class="slide"' 'img src="xttps://site.com/files/r_1000,kljg894/43k5j/35h43jkl.jpg' '/div'
• 'div class="slide"' 'img src="xttps://site.com/files/r_2000,kljg894/43k5j/35h43jkl.jpg' '/div'
• 'div class="slide"' 'img src="xttps://site.com/files/r_3000,kljg894/43k5j/35h43jkl.jpg' '/div'

Need to get a link containing only "r_3000"

This code gets all the links:

imglink = soup.find_all('img')
print(imglink)

I looked through and tried many tips. For example:

('img', string="*r_3000*"), ('img', string=re.compile('r_3000') and ('img', string=lambda s: 'r_3000' in s) and many others, but all this does not work :(

Help me please.

Solution

Many ways you can do that.Try css selector.

from bs4 import BeautifulSoup
html='''<div class="slide"><img src="xttps://site.com/files/r_1000,kljg894/43k5j/35h43jkl.jpg"></div>
<div class="slide"> <img src="xttps://site.com/files/r_2000,kljg894/43k5j/35h43jkl.jpg"></div>
<div class="slide"><img src="xttps://site.com/files/r_3000,kljg894/43k5j/35h43jkl.jpg"></div>'''
soup=BeautifulSoup(html,"html.parser")
for item in soup.select("img[src*='r_3000']"):
    print(item['src'])

Answered By - KunduK