[FIXED] List of Dictionary - How to combine a list of dictionary Python

Issue

a =[{
    "id":"1",
    "Name":'BK',
    "Age":'56'
},
{
    "id":"1",
    "Sex":'Male'
},
{
    "id":"2",
    "Name":"AK",
    "Age":"32"
}]

I have a list of dictionary with a person information split in multiple dictionary as above for ex above id 1's information is contained in first 2 dictionary , how can i get an output of below

{1: {'Name':'BK','Age':'56','Sex':'Male'}, 2: { 'Name': 'AK','Age':'32'}}

Solution

You can use a defaultdict to collect the results.

from collections import defaultdict

a =[{ "id":"1", "Name":'BK', "Age":'56' }, { "id":"1", "Sex":'Male' }, { "id":"2", "Name":"AK", "Age":"32" }]

results = defaultdict(dict)
key = lambda d: d['id']

for a_dict in a:
    results[a_dict.pop('id')].update(a_dict)

This gives you:

>>> results
defaultdict(<class 'dict'>, {'1': {'Name': 'BK', 'Age': '56', 'Sex': 'Male'}, '2': {'Name': 'AK', 'Age': '32'}})

The defaultdict type behaves like a normal dict, except that when you reference an unknown value, a default value is returned. This means that as the dicts in a are iterated over, the values (except for id) are updated onto either an existing dict, or an automatic newly created one.

How does collections.defaultdict work?

Answered By - Richard Dodson