[FIXED] Parse ½ as 0.5 in Python 2.7

Issue

I am scraping this link with BeautifulSoup4

I am parsing page HTML like this

page = BeautifulSoup(page.replace('ISO-8859-1', 'utf-8'),"html5lib")

You can see the values like these -4 -115 (separated by -)

I want both values in a list so I am using this regex.

value = re.findall(r'[+-]?\d+', value)

It works perfectly but not for these values +2½ -102, I only get [-102]

To tackle this, I tried this too

value = value.replace("½","0.5")
value = re.findall(r'[+-]?\d+', value)

but this gives me error about encoding saying I have to set encoding of my file.

I also tried setting encoding=utf-8 at top of file but still gives same error.

I need to ask how do I convert ½ to 0.5

Solution

To embed Unicode literals like ½ in your Python 2 script you need to use a special comment at the top of your script that lets the interpreter know how the Unicode has been encoded. If you want to use UTF-8 you will also need to tell your editor to save the file as UTF-8. And if you want to print Unicode text make sure your terminal is set to use UTF-8, too.

Here's a short example, tested on Python 2.6.6

# -*- coding: utf-8 -*-

value = "a string with fractions like 2½ in it"
value = value.replace("½",".5")
print(value)

output

a string with fractions like 2.5 in it

Note that I'm using ".5" as the replacement string; using "0.5" would convert "2½" to "20.5", which would not be correct.

---

Actually, those strings should be marked as Unicode strings, like this:

# -*- coding: utf-8 -*-

value = u"a string with fractions like 2½ in it"
value = value.replace(u"½", u".5")
print(value)

For further information on using Unicode in Python, please see Pragmatic Unicode, which was written by SO veteran Ned Batchelder.

---

I should also mention that you will need to change your regex pattern so that it allows a decimal point in numbers. Eg:

# -*- coding: utf-8 -*-
from __future__ import print_function
import re

pat = re.compile(r'[-+]?(?:\d*?[.])?\d+', re.U) 

data = u"+2½ -105 -2½ -115 +2½ -105 -2½ -115 +2½ -102 -2½ -114"
print(data)
print(pat.findall(data.replace(u"½", u".5")))

output

+2½ -105 -2½ -115 +2½ -105 -2½ -115 +2½ -102 -2½ -114
[u'+2.5', u'-105', u'-2.5', u'-115', u'+2.5', u'-105', u'-2.5', u'-115', u'+2.5', u'-102', u'-2.5', u'-114']

Answered By - PM 2Ring