[FIXED] How to get href using beautiful soup

Issue

I have a list of <li> each containing an <a> tag href url value and a <span> with its url title . I am trying to get the url by the span tag's title value. This is my example:

<li><a href="http://someurl"><span>Title of URL</span></a></li>

This is my last attempt:

soup.select_one('span:-soup-contains("Title of URL:")').find_previous_sibling(text=True)

But that won't work since the span is IN the <a> tag. I've tried countless other variations that I have since deleted.

If anyone can help I'd be grateful.

Solution

Just select correct <a>:

from bs4 import BeautifulSoup

html_text = """\
<li><a href="http://someurl"><span>Title of URL</span></a></li>"""

soup = BeautifulSoup(html_text, "html.parser")

url = soup.select_one('a:-soup-contains("Title of URL")')["href"]
print(url)

Prints:

http://someurl

Answered By - Andrej Kesely