Issue
This is a pretty standard interview question. Find the longest substring without repeating characters. Here are the test cases,
abcabcbb -> 3
bbbbb -> 1
pwwkew -> 3
bpfbhmipx -> 7
tmmzuxt -> 5
Here's my code which uses a pretty simple approach with 2 pointers.
def lengthOfLongestSubstring(s):
checklist = {}
starting_index_of_current_substring = 0
length_of_longest_substring = 0
for i, v in enumerate(s):
if v in checklist:
starting_index_of_current_substring = checklist[v] + 1
else:
length_of_current_substring = i - starting_index_of_current_substring + 1
length_of_longest_substring = max(length_of_current_substring, length_of_longest_substring)
checklist[v] = i
return length_of_longest_substring
My code passes all the test cases except the last one (actual 4, expected 5). Can someone help me modify the code to take care of the last test case. I don't wish to reinvent the algorithm.
Solution
This post is pretty old, but I think my solution fixes the bug in the original code.
def lengthOfLongestSubstring(s):
checklist = {}
starting_index_of_current_substring = 0
length_of_longest_substring = 0
for i, v in enumerate(s):
if v in checklist:
if checklist[v] >= starting_index_of_current_substring:
starting_index_of_current_substring = checklist[v] + 1
length_of_current_substring = i - starting_index_of_current_substring + 1
length_of_longest_substring = max(length_of_current_substring, length_of_longest_substring)
checklist[v] = i
return length_of_longest_substring
Answered By - user11751463
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