[FIXED] prepopulate numpy array with fixed values

Issue

How can I prepopulate while initializing numpy array with fixed values? I tried generating list and using that as a fill.

>>> c = np.empty(5)
>>> c
array([0.0e+000, 9.9e-324, 1.5e-323, 2.0e-323, 2.5e-323])
>>> np.array(list(range(0,10,1)))
array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> 
 
>>> c.fill(np.array(list(range(0,10,1))))
TypeError: only length-1 arrays can be converted to Python scalars

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: setting an array element with a sequence.

>>> c.fill([np.array(list(range(0,10,1)))])
TypeError: float() argument must be a string or a real number, not 'list'

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: setting an array element with a sequence.

Expected -

array([[0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]])

Solution

np.tile(np.arange(10), (5,1))

np.arange(10) creates an array of integers from 0 to 9

np.tile(..., (5,1)) tiles copies of the array - 5 copies going "down" (new rows) and 1 "across" (1 copy within each row)

Answered By - AJ Biffl