[FIXED] how to pass the function name to be used in python

Issue

i have the following json template

template.py

from string import Template

test1 = Template(u'''\
{
    "data": {
       "name": "$name"
    }
}
''')

and to generate the JSONs I use JSONGen.py

import template

class JSONGen:
    result1 = template.test1.safe_substitute(
        name = 'SomeName'
    )
    print(result1)

now that works, it produces the JSON but i'm trying to create a function that accepts the template name and calls it something like

JSONGenV2.py

import template

class JSONGenV2:

    def template_func(self, templateName):
        generatedTemplate = template.templateName.safe_substitute(
            name = 'SomeName'
        )

        print (generatedTemplate)

    template_func(test1)

now what i want to achieve is to use 'templateName' contents to be the template to call, as it is right now

template.templateName.safe_substitute

gives me an error saying 'templateName' doesn't exist, how can 'templateName' be a changed to the value passed in tihs case 'test1' so it would call

template.test1.safe_substitute

Thank you

Solution

Use getattr(), usage like this:

getattr(object, name[, default])

Return the value of the named attribute of object. name must be a string. If the string is the name of one of the object’s attributes, the result is the value of that attribute. For example, getattr(x, 'foobar') is equivalent to x.foobar. If the named attribute does not exist, default is returned if provided, otherwise AttributeError is raised.

Applied to your code:

class JSONGenV2:

    def template_func(self, templateName):
        generatedTemplate = getattr(template, templateName).safe_substitute(
            name = 'SomeName'
        )

        print (generatedTemplate)

    template_func(test1)

Answered By - r.ook